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27y-18y^2=0
a = -18; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-18)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-18}=\frac{-54}{-36} =1+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-18}=\frac{0}{-36} =0 $
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